In this paper we prove the following results. Every element of a ring R is a sum of two commuting 6-potent elements if and only if R is isomorphic to R_1×R_2×R_3, where R_1 is isomorphic to a subdirect product of Z_2's, R_2 is isomorphic to a subdirect product of Z_3's and R_3 is isomorphic to a subdirect product of Z_11's. Also if every element of a ring R is sum of two 6-potent and one nilpotent all commute each other then R is isomorphic to R_1×R_2×R_3, where J(R_1) is nil and R_1/J(R_1) is a subdirect product of rings isomorphic to either of the rings Z_2, F_4, M_2(F_2) and M_2(F_4), a^{81}-a is nilpotent for every a in R2 , J(R_3) is nil and R_3/J(R_3) is a subdirect product of Z_11's.
Deka, K., & Saikia, H. (2024). Ring in which every element is sum of two 6-potent elements. Journal of Algebra and Related Topics, (), -. doi: 10.22124/jart.2024.26096.1605
MLA
K. N. Deka; H. K. Saikia. "Ring in which every element is sum of two 6-potent elements". Journal of Algebra and Related Topics, , , 2024, -. doi: 10.22124/jart.2024.26096.1605
HARVARD
Deka, K., Saikia, H. (2024). 'Ring in which every element is sum of two 6-potent elements', Journal of Algebra and Related Topics, (), pp. -. doi: 10.22124/jart.2024.26096.1605
VANCOUVER
Deka, K., Saikia, H. Ring in which every element is sum of two 6-potent elements. Journal of Algebra and Related Topics, 2024; (): -. doi: 10.22124/jart.2024.26096.1605